lc061

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Published: Aug 9, 2023 License: GPL-3.0 Imports: 2 Imported by: 0

README

61.旋转链表

1. 题目描述

给你一个链表的头节点 head ,旋转链表,将链表每个节点向右移动  k * * 个位置。

 

示例 1:


输入:head = [1,2,3,4,5], k = 2
输出:[4,5,1,2,3]

示例 2:


输入:head = [0,1,2], k = 4
输出:[2,0,1]

 

提示:

  • 链表中节点的数目在范围 [0, 500]
  • -100 <= Node.val <= 100
  • 0 <= k <= 2 * 10^9

标签 链表 双指针

2. 解题

若链表的长度为len,则链表移动的次数为(k%len),要达到反转的效果,可以先把原链表的尾部和头部相连,再从新链表的头结点前断开即可。

Documentation

Index

Constants

This section is empty.

Variables

This section is empty.

Functions

This section is empty.

Types

type ListNode

type ListNode struct {
	Val  int
	Next *ListNode
}

func BuildCircleListWithNoHead

func BuildCircleListWithNoHead(list []int, cursor int) *ListNode

BuildCircleListWithNoHead build a circle list, which tail point to list[cursor]

func BuildListWithHead

func BuildListWithHead(data []int) *ListNode

func BuildListWithNoHead

func BuildListWithNoHead(nums []int) *ListNode

func (*ListNode) HasCycle

func (l *ListNode) HasCycle() (bool, *ListNode)

HasCycle check if linklist has cycle structure, if not, return false, nil, if yes, return true and the cycle start node

func (*ListNode) Index

func (l *ListNode) Index(target int) *ListNode

Index return the node which value equals target

func (*ListNode) Len

func (l *ListNode) Len() int

Len return list length, when list has cycle structure, return -1

func (*ListNode) Slice

func (l *ListNode) Slice() []int

Slice return slice which contains all node's values in order.

func (*ListNode) String

func (l *ListNode) String() string

String implements Stringer interface.

func (*ListNode) Tail

func (l *ListNode) Tail() *ListNode

Tail return last list node

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