lc086

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Published: Aug 9, 2023 License: GPL-3.0 Imports: 2 Imported by: 0

README

86.分隔链表

1. 题目描述

给你一个链表的头节点 head 和一个特定值 x ,请你对链表进行分隔,使得所有 小于 x 的节点都出现在 大于或等于 x 的节点之前。

你应当 保留 两个分区中每个节点的初始相对位置。

 

示例 1:


输入:head = [1,4,3,2,5,2], x = 3
输出:[1,2,2,4,3,5]

示例 2:


输入:head = [2,1], x = 2
输出:[1,2]

 

提示:

  • 链表中节点的数目在范围 [0, 200]
  • -100 <= Node.val <= 100
  • -200 <= x <= 200

标签 链表 双指针

2. 解题

将链表按大小分为两个链表,一个存储小于x的节点,一个存储大于等于x的节点,最后将小值链表末尾接到大值链表的头节点。
设置两个哑节点smalllist和largelist,并设置指针small和large分别指向他们。若值小于x,则链接到small指针后,否则链接到large后。最后将large.next置为nil,将small.next置为largelist.next。

Documentation

Index

Constants

This section is empty.

Variables

This section is empty.

Functions

This section is empty.

Types

type ListNode

type ListNode struct {
	Val  int
	Next *ListNode
}

func BuildCircleListWithNoHead

func BuildCircleListWithNoHead(list []int, cursor int) *ListNode

BuildCircleListWithNoHead build a circle list, which tail point to list[cursor]

func BuildListWithHead

func BuildListWithHead(data []int) *ListNode

func BuildListWithNoHead

func BuildListWithNoHead(nums []int) *ListNode

func (*ListNode) HasCycle

func (l *ListNode) HasCycle() (bool, *ListNode)

HasCycle check if linklist has cycle structure, if not, return false, nil, if yes, return true and the cycle start node

func (*ListNode) Index

func (l *ListNode) Index(target int) *ListNode

Index return the node which value equals target

func (*ListNode) Len

func (l *ListNode) Len() int

Len return list length, when list has cycle structure, return -1

func (*ListNode) Slice

func (l *ListNode) Slice() []int

Slice return slice which contains all node's values in order.

func (*ListNode) String

func (l *ListNode) String() string

String implements Stringer interface.

func (*ListNode) Tail

func (l *ListNode) Tail() *ListNode

Tail return last list node

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