lc206

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Published: Aug 9, 2023 License: GPL-3.0 Imports: 2 Imported by: 0

README

206.反转链表

1. 题目描述

给你单链表的头节点 head ,请你反转链表,并返回反转后的链表。  

示例 1:


输入:head = [1,2,3,4,5]
输出:[5,4,3,2,1]

示例 2:


输入:head = [1,2]
输出:[2,1]

示例 3:


输入:head = []
输出:[]

 

提示:

  • 链表中节点的数目范围是 [0, 5000]
  • -5000 <= Node.val <= 5000  

进阶: 链表可以选用迭代或递归方式完成反转。你能否用两种方法解决这道题?

标签 递归 链表

2. 解题

采用迭代的方法,在遍历链表时,将当前节点的next指针改为指向前一个节点prev。

Documentation

Index

Constants

This section is empty.

Variables

This section is empty.

Functions

This section is empty.

Types

type ListNode

type ListNode struct {
	Val  int
	Next *ListNode
}

func BuildCircleListWithNoHead

func BuildCircleListWithNoHead(list []int, cursor int) *ListNode

BuildCircleListWithNoHead build a circle list, which tail point to list[cursor]

func BuildListWithHead

func BuildListWithHead(data []int) *ListNode

func BuildListWithNoHead

func BuildListWithNoHead(nums []int) *ListNode

func (*ListNode) HasCycle

func (l *ListNode) HasCycle() (bool, *ListNode)

HasCycle check if linklist has cycle structure, if not, return false, nil, if yes, return true and the cycle start node

func (*ListNode) Index

func (l *ListNode) Index(target int) *ListNode

Index return the node which value equals target

func (*ListNode) Len

func (l *ListNode) Len() int

Len return list length, when list has cycle structure, return -1

func (*ListNode) Slice

func (l *ListNode) Slice() []int

Slice return slice which contains all node's values in order.

func (*ListNode) String

func (l *ListNode) String() string

String implements Stringer interface.

func (*ListNode) Tail

func (l *ListNode) Tail() *ListNode

Tail return last list node

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