goden0205

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v0.0.0-...-b071cee Latest Latest Go to latest Published: Aug 9, 2023 License: GPL-3.0 Imports: 2 Imported by: 0

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github.com/CodeHanHan/leetcode-go

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README ¶

面试题 02.05.链表求和

1. 题目描述

给定两个用链表表示的整数，每个节点包含一个数位。

这些数位是反向存放的，也就是个位排在链表首部。

编写函数对这两个整数求和，并用链表形式返回结果。

示例：

输入：(7 -> 1 -> 6) + (5 -> 9 -> 2)，即617 + 295
输出：2 -> 1 -> 9，即912

进阶： 思考一下，假设这些数位是正向存放的，又该如何解决呢?

示例：

输入：(6 -> 1 -> 7) + (2 -> 9 -> 5)，即617 + 295
输出：9 -> 1 -> 2，即912

标签 递归 链表 数学

2. 解题

merge

Documentation ¶

Index ¶

type ListNode

Constants ¶

This section is empty.

Variables ¶

This section is empty.

Functions ¶

This section is empty.

Types ¶

type ListNode ¶

type ListNode struct {
	Val  int
	Next *ListNode
}

func BuildCircleListWithNoHead ¶

func BuildCircleListWithNoHead(list []int, cursor int) *ListNode

BuildCircleListWithNoHead build a circle list, which tail point to list[cursor]

func BuildListWithHead ¶

func BuildListWithHead(data []int) *ListNode

func BuildListWithNoHead ¶

func BuildListWithNoHead(nums []int) *ListNode

func (*ListNode) HasCycle ¶

func (l *ListNode) HasCycle() (bool, *ListNode)

HasCycle check if linklist has cycle structure, if not, return false, nil, if yes, return true and the cycle start node

func (*ListNode) Index ¶

func (l *ListNode) Index(target int) *ListNode

Index return the node which value equals target

func (*ListNode) Len ¶

func (l *ListNode) Len() int

Len return list length, when list has cycle structure, return -1

func (*ListNode) Slice ¶

func (l *ListNode) Slice() []int

Slice return slice which contains all node's values in order.

func (*ListNode) String ¶

func (l *ListNode) String() string

String implements Stringer interface.

func (*ListNode) Tail ¶

func (l *ListNode) Tail() *ListNode

Tail return last list node

Source Files ¶

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