README
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- 扁平化嵌套列表迭代器 medium 给你一个嵌套的整型列表。请你设计一个迭代器，使其能够遍历这个整型列表中的所有整数。
列表中的每一项或者为一个整数，或者是另一个列表。其中列表的元素也可能是整数或是其他列表。
示例 1:
输入: [[1,1],2,[1,1]]
输出: [1,1,2,1,1]
解释: 通过重复调用 next 直到 hasNext 返回 false，next 返回的元素的顺序应该是: [1,1,2,1,1]。
示例 2:
输入: [1,[4,[6]]]
输出: [1,4,6]
解释: 通过重复调用 next 直到 hasNext 返回 false，next 返回的元素的顺序应该是: [1,4,6]。
Documentation
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Index ¶
Constants ¶
This section is empty.
Variables ¶
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Functions ¶
This section is empty.
Types ¶
type NestedInteger ¶
type NestedInteger struct {
}
This is the interface that allows for creating nested lists. You should not implement it, or speculate about its implementation
func (*NestedInteger) Add ¶
func (this *NestedInteger) Add(elem NestedInteger)
Set this NestedInteger to hold a nested list and adds a nested integer to it.
func (NestedInteger) GetInteger ¶
func (this NestedInteger) GetInteger() int
Return the single integer that this NestedInteger holds, if it holds a single integer The result is undefined if this NestedInteger holds a nested list So before calling this method, you should have a check
func (NestedInteger) GetList ¶
func (this NestedInteger) GetList() []*NestedInteger
Return the nested list that this NestedInteger holds, if it holds a nested list The list length is zero if this NestedInteger holds a single integer You can access NestedInteger's List element directly if you want to modify it
func (NestedInteger) IsInteger ¶
func (this NestedInteger) IsInteger() bool
Return true if this NestedInteger holds a single integer, rather than a nested list.
func (*NestedInteger) SetInteger ¶
func (n *NestedInteger) SetInteger(value int)
Set this NestedInteger to hold a single integer.
type NestedIterator ¶
type NestedIterator struct {
Data []*NestedInteger
}
func Constructor ¶
func Constructor(nestedList []*NestedInteger) *NestedIterator
func (*NestedIterator) HasNext ¶
func (this *NestedIterator) HasNext() bool
func (*NestedIterator) Next ¶
func (this *NestedIterator) Next() int
Source Files