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Strings s1 and s2 are k-similar (for some non-negative integer k) if we can swap the positions of two letters in s1 exactly k times so that the resulting string equals s2.
Given two anagrams s1 and s2, return the smallest k for which s1 and s2 are k-similar.
Example 1:
Input: s1 = "ab", s2 = "ba"
Output: 1
Example 2:
Input: s1 = "abc", s2 = "bca"
Output: 2
Example 3:
Input: s1 = "abac", s2 = "baca"
Output: 2
Example 4:
Input: s1 = "aabc", s2 = "abca"
Output: 2
Constraints:
1 <= s1.length <= 20
s2.length == s1.length
s1 and s2 contain only lowercase letters from the set {'a', 'b', 'c', 'd', 'e', 'f'}.
s2 is an anagram of s1.
[String]
[Breadth-First Search]
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