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Design an algorithm that accepts a stream of characters and checks if a suffix of these characters is a string of a given array of strings words
.
For example, if words = ["abc", "xyz"]
and the stream added the four characters (one by one) 'a'
, 'x'
, 'y'
, and 'z'
, your algorithm should detect that the suffix "xyz"
of the characters "axyz"
matches "xyz"
from words
.
Implement the StreamChecker
class:
StreamChecker(String[] words)
Initializes the object with the strings array words
.
boolean query(char letter)
Accepts a new character from the stream and returns true
if any non-empty suffix from the stream forms a word that is in words
.
Example 1:
Input
["StreamChecker", "query", "query", "query", "query", "query", "query", "query", "query", "query", "query", "query", "query"]
[[["cd", "f", "kl"]], ["a"], ["b"], ["c"], ["d"], ["e"], ["f"], ["g"], ["h"], ["i"], ["j"], ["k"], ["l"]]
Output
[null, false, false, false, true, false, true, false, false, false, false, false, true]
Explanation
StreamChecker streamChecker = new StreamChecker(["cd", "f", "kl"]);
streamChecker.query("a"); // return False
streamChecker.query("b"); // return False
streamChecker.query("c"); // return False
streamChecker.query("d"); // return True, because 'cd' is in the wordlist
streamChecker.query("e"); // return False
streamChecker.query("f"); // return True, because 'f' is in the wordlist
streamChecker.query("g"); // return False
streamChecker.query("h"); // return False
streamChecker.query("i"); // return False
streamChecker.query("j"); // return False
streamChecker.query("k"); // return False
streamChecker.query("l"); // return True, because 'kl' is in the wordlist
Constraints:
1 <= words.length <= 2000
1 <= words[i].length <= 2000
words[i]
consists of lowercase English letters.
letter
is a lowercase English letter.
- At most
4 * 104
calls will be made to query.
[Design]
[Trie]
[Array]
[String]
[Data Stream]
Hints
Hint 1
Put the words into a trie, and manage a set of pointers within that trie.