q010_regular_expression_matching

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Published: Feb 15, 2021 License: MIT Imports: 2 Imported by: 0

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[Hard] Regular Expression Matching https://leetcode.com/problems/regular-expression-matching/

Given an input string (s) and a pattern (p), implement regular expression matching with support for '.' and '*'.

'.' Matches any single character. '*' Matches zero or more of the preceding element.

The matching should cover the entire input string (not partial).

Note:

s could be empty and contains only lowercase letters a-z.
p could be empty and contains only lowercase letters a-z, and characters like . or *.

Example 1:

Input: s = "aa" p = "a" Output: false Explanation: "a" does not match the entire string "aa".

Example 2:

Input: s = "aa" p = "a*" Output: true Explanation: '*' means zero or more of the preceding element, 'a'. Therefore, by repeating 'a' once, it becomes "aa".

Example 3:

Input: s = "ab" p = ".*" Output: true Explanation: ".*" means "zero or more (*) of any character (.)".

Example 4:

Input: s = "aab" p = "c*a*b" Output: true Explanation: c can be repeated 0 times, a can be repeated 1 time. Therefore, it matches "aab".

Example 5:

Input: s = "mississippi" p = "mis*is*p*." Output: false

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